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Question 13 of 155MediumMCQ
If α>β>γ>0\alpha >\beta >\gamma >0, then the expression cot⁡−1β+(1+β2)(α−β)+cot⁡−1γ+(1+γ2)(β−γ)+cot⁡−1α+(1+α2)(γ−α){\cot }^{-1}{\beta +\frac{(1+{\beta }^{2})}{(\alpha -\beta )}}+{\cot }^{-1}{\gamma +\frac{(1+{\gamma }^{2})}{(\beta -\gamma )}}+{\cot }^{-1}{\alpha +\frac{(1+{\alpha }^{2})}{(\gamma -\alpha )}} is equal to :
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