Official solution
Given sin-1\[\left( {{x \over 5}} \right)\] + cosec-1\[\left( {{5 \over 4}} \right)\] = \[{\pi \over 2}\]
\[ \Rightarrow \] sin-1\[\left( {{x \over 5}} \right)\] + sin-1\[\left( {{4 \over 5}} \right)\] = \[{\pi \over 2}\]
\[ \Rightarrow \] sin-1\[\left( {{x \over 5}} \right)\] = \[{\pi \over 2}\] - sin-1\[\left( {{4 \over 5}} \right)\]
\[ \Rightarrow \] sin-1\[\left( {{x \over 5}} \right)\] = cos-1\[\left( {{4 \over 5}} \right)\]
\[ \Rightarrow \] \[{x \over 5}\] = sin(cos-1\[ {{4 \over 5}}\])
\[ \Rightarrow \] \[{x \over 5}\] = sin(sin-1\[ {{3 \over 5}}\])
\[ \Rightarrow \] \[{x \over 5}\] = \[{3 \over 5}\]
\[ \Rightarrow \] x = 3