The value of ∫π/3π/2sinx(1+cosx)2+3sinxdx is equal to:
Solutions · 1
Official solution
Split as 2∫sinx(1+cosx)dx+3∫1+cosxdx.
For the second: ∫π/3π/21+cosxdx=∫(csc2(x/2)−cot(x/2)csc(x/2))dx-type manipulation gives 1−31 over the limits.
For the first, with t=tan(x/2): ∫2t1+t2dt-type reduction gives 61+21ln3 over the limits.
Combining:
\[I = 2\left(\frac16+\frac12\ln\sqrt{3}\right) + 3\left(1-\frac1{\sqrt{3}}\right) = \frac{10}3+\ln\sqrt{3}-\sqrt{3}\]