Question 86 of 416MediumMCQ
If [x] denotes the greatest integer ≤x, then the value of ∫12x2e[x]+[x3]dx is: Solutions · 1
Official solution
On (1,2), [x]=1. Let x3=t, 3x2dx=dt:
\[I = \int_1^2 x^2e^{1+[x^3]}\,dx = \frac{e}3\int_1^8 e^{[t]}\,dt = \frac{e}3\left(\int_1^2e\,dt+\int_2^3e^2\,dt+\cdots+\int_7^8e^7\,dt\right)\]
\[= \frac{e}3\left(e+e^2+\cdots+e^7\right) = \frac{e^2}3(1+e+\cdots+e^6) = \frac{e^2}3\cdot\frac{e^7-1}{e-1}\]
\[I = \frac{e^2}{3}\cdot\frac{(e-1)(e^6+e^5+\cdots+1)}{e-1}=\frac{e}{3}(e-1)\cdot\frac{e^7-1}{e-1} = e(e^7-1) = e^8-e\] Answer the question to unlock