Question 75 of 416MediumNUMERICAL
The value of π8∫0π/2(sinx)2023+(cosx)2023(cosx)2023dx is \_\_\_\_
Answer: 2 Solutions · 1
Official solution
Let I=π8∫0π/2(sinx)2023+(cosx)2023(cosx)2023dx. Using ∫0af(x)dx=∫0af(a−x)dx:
\[I = \frac8\pi\int_0^{\pi/2}\frac{(\sin x)^{2023}}{(\sin x)^{2023}+(\cos x)^{2023}}\,dx\]
Adding both expressions for I:
\[2I = \frac8\pi\int_0^{\pi/2}1\,dx = \frac8\pi\cdot\frac\pi2 = 4 \implies I=2\] Answer the question to unlock