Question 57 of 416MediumMCQ
Let f and g be functions with g(x)=∫0xtf(t)dt satisfying g(x3)=x6+x7. Then r=1∑15f(r3) is equal to: Solutions · 1
Official solution
Let u=x3: g(u)=u2+u7/3. Then g′(u)=2u+37u4/3=uf(u), so
\[f(u) = 2+\frac73u^{1/3}\]
\[f(r^3) = 2+\frac73r\]
\[\sum_{r=1}^{15}f(r^3) = \sum_{r=1}^{15}\left(2+\frac73r\right) = 30 + \frac73\cdot\frac{15\cdot16}{2} = 30+280 = 310\] Answer the question to unlock