Question 38 of 416MediumMCQ
Let f be a polynomial function such that f(x2+1)=x4+5x2+2, for all x∈R. Then ∫03f(x)dx is equal to: Solutions · 1
Official solution
Let t=x2+1, so x2=t−1:
\[f(t) = (t-1)^2+5(t-1)+2 = t^2-2t+1+5t-5+2 = t^2+3t-2\]
So f(x)=x2+3x−2.
\[\int_0^3 f(x)\,dx = \left[\frac{x^3}{3}+\frac{3x^2}{2}-2x\right]_0^3 = 9+\frac{27}{2}-6 = 3+\frac{27}{2} = \frac{33}{2}\] Answer the question to unlock