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Exams
Joint Entrance Examination
Mathematics
Indefinite Integrals
Question 369
Question 369 of 416
Medium
MCQ
lim
n
→
∞
1
p
+
2
p
+
3
p
+
⋯
+
n
p
n
p
+
1
\displaystyle\lim_{n\to\infty} \dfrac{1^p+2^p+3^p+\cdots+n^p}{n^{p+1}}
n
→
∞
lim
n
p
+
1
1
p
+
2
p
+
3
p
+
⋯
+
n
p
is:
A
1
p
+
1
\dfrac{1}{p+1}
p
+
1
1
B
1
1
−
p
\dfrac{1}{1-p}
1
−
p
1
C
1
p
−
1
p
−
1
\dfrac1p-\dfrac{1}{p-1}
p
1
−
p
−
1
1
D
1
p
+
2
\dfrac{1}{p+2}
p
+
2
1
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Official solution
lim
n
→
∞
∑
r
=
1
n
r
p
n
p
⋅
n
=
∫
0
1
x
p
d
x
=
[
x
p
+
1
p
+
1
]
0
1
=
1
p
+
1
\lim_{n\to\infty}\sum_{r=1}^n \dfrac{r^p}{n^p\cdot n} = \int_0^1 x^p\,dx = \left[\dfrac{x^{p+1}}{p+1}\right]_0^1 = \dfrac{1}{p+1}
lim
n
→
∞
∑
r
=
1
n
n
p
⋅
n
r
p
=
∫
0
1
x
p
d
x
=
[
p
+
1
x
p
+
1
]
0
1
=
p
+
1
1
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