If α=23∫023log2(x2+4)dx+∫242x−4dx, then α2 is equal to \_\_\_\_\_\_\_\_.
Answer: 192
Solutions · 1
Official solution
Using the standard property for inverse-function pairs, ∫abf(x)dx+∫f(a)f(b)f−1(x)dx=bf(b)−af(a), with f(x)=log2(x2+4), a=0,b=23 (so f(0)=2, f(23)=4):
\[\alpha = (2\sqrt{3})(4) - (0)(2) = 8\sqrt{3}\]
\[\alpha^2 = 192\]