Question 349 of 416MediumMCQ
If I1=∫012x2dx, I2=∫012x3dx, I3=∫122x2dx and I4=∫122x3dx, then: Solutions · 1
Official solution
\[{I_1} = \int\limits_0^1 {{2^{{x^2}}}} dx,\,{I_2} = \int\limits_0^1 {{2^{{x^3}}}} dx,\]
\[ = {I_3} = \int\limits_0^1 {{2^{{x^2}}}} dx,\,\]
\[{I_4} = \int\limits_0^1 {{2^{{x^3}}}} dx\,\,\]
\[\forall 0 < x < 1,\,{x^2} > {x^3}\]
\[ \Rightarrow \int\limits_0^1 {{2^{{x^2}}}} \,dx > \int\limits_0^1 {{2^{{x^3}}}} dx\]
and \[\int\limits_1^2 {{2^{{x^3}}}dx} > \int\limits_1^2 {{2^{{x^2}}}dx} \]
\[ \Rightarrow {I_1} > {I_2}\] and I4>I3 Answer the question to unlock