Question 267 of 416MediumMCQ
The value of ∫0π/2sinx+cosxsin3xdx is: Solutions · 1
Official solution
Let I=∫0π/2sinx+cosxsin3xdx …(1). Using x→2π−x:
\[I=\int_0^{\pi/2}\frac{\cos^3x}{\sin x+\cos x}dx\ \ldots(2)\]
Adding (1) and (2):
\[2I=\int_0^{\pi/2}\frac{\sin^3x+\cos^3x}{\sin x+\cos x}dx=\int_0^{\pi/2}(1-\sin x\cos x)\,dx=\int_0^{\pi/2}\left(1-\frac12\sin2x\right)dx\]
\[2I=\left[x+\frac14\cos2x\right]_0^{\pi/2}=\frac\pi2-1\Rightarrow I=\frac{\pi-1}4\] Answer the question to unlock