Question 259 of 416MediumMCQ
If ∫esecx(secxtanxf(x)+(secxtanx+sec2x))dx=esecxf(x)+C, then a possible choice of f(x) is: Solutions · 1
Official solution
Using ∫eg(x)(g′(x)f(x)+f′(x))dx=eg(x)f(x)+C with g(x)=secx (so g′(x)=secxtanx), comparing f′(x)=secxtanx+sec2x:
\[f(x)=\int(\sec x\tan x+\sec^2x)\,dx=\sec x+\tan x+C\]
Taking C=21: f(x)=secx+tanx+21 Answer the question to unlock