Let {x} and [x] denote the fractional part of x and the greatest integer ≤x respectively of a real number x. If ∫0n{x}dx, ∫0n[x]dx and 10(n2−n), (n∈N,n>1) are three consecutive terms of a G.P., then n is equal to\_\_\_\_\_\_\_.
Answer: 21
Solutions · 1
Official solution
\[\int_0^n\{x\}dx=n\int_0^1x\,dx=\frac n2,\qquad \int_0^n[x]dx=\int_0^n(x-\{x\})dx=\frac{n^2}2-\frac n2\]
Since these along with 10(n2−n) are in G.P.:
\[\left(\frac{n^2-n}2\right)^2=\frac n2\cdot10(n^2-n)\Rightarrow n^2=21n\Rightarrow n=21\]