If xϕ(x)=∫5x(3t2−2ϕ′(t))dt, x>−2, and ϕ(0)=4, then ϕ(2) is
Answer: 4
Solutions · 1
Official solution
\[x\phi(x)=\int_5^x(3t^2-2\phi'(t))dt=\left[t^3-2\phi(t)\right]_5^x=(x^3-125)-2[\phi(x)-\phi(5)]\]
At x=0: 0=−125−2[4−ϕ(5)]⇒ϕ(5)=2133
At x=2: 2ϕ(2)=(8−125)−2[ϕ(2)−2133]⇒4ϕ(2)=16⇒ϕ(2)=4