Question 16 of 416MediumMCQ
For x∈(−2π,2π), if y(x)=∫cscxsecx+tanxsin2xcscx+sinxdx, and x→(2π)−limy(x)=0 then y(4π) is equal to Solutions · 1
Official solution
y(x)=∫1+sin4x(1+sin2x)cosxdxsinx=t=∫t4+11+t2dt=21tan−12(t−t1)+Cx=2π,t=1∴C=0y(4π)=21tan−1(−21) Answer the question to unlock