Question 150 of 416MediumMCQ
The integral ∫0π/23+2sinx+cosx1dx is equal to: Solutions · 1
Official solution
With t=tan(x/2):
\[I = \int_0^1\frac{2\,dt}{3(1+t^2)+2(2t)+(1-t^2)} = \int_0^1\frac{2\,dt}{4+4t+2t^2} = \int_0^1\frac{dt}{(t+1)^2+1}\]
\[= \big[\tan^{-1}(t+1)\big]_0^1 = \tan^{-1}2-\tan^{-1}1 = \tan^{-1}(2)-\frac\pi4\] Answer the question to unlock