This is a Riemann sum: n→∞limn1k=1∑n(1+n2k2)(1+nk)1=∫01(1+x2)(1+x)dx
Partial fractions: (1+x2)(1+x)1=1+x1/2+1+x2−x/2+1/2
\[\int_0^1\left[\frac1{2(1+x)}-\frac{x}{2(1+x^2)}+\frac1{2(1+x^2)}\right]dx = \frac12\ln2-\frac14\ln2+\frac12\cdot\frac\pi4 = \frac14\ln2+\frac\pi8\]