Exams Joint Entrance Examination Mathematics Indefinite Integrals Question 10 Question 10 of 416 Medium MCQ
Let I ( x ) = ∫ d x ( x − 11 ) 11 13 ( x + 15 ) 15 13 I(x)=\int \frac{dx}{(x-11{)}^{\frac{11}{13}}(x+15{)}^{\frac{15}{13}}} I ( x ) = ∫ ( x − 11 ) 13 11 ( x + 15 ) 13 15 d x . If I ( 37 ) − I ( 24 ) = 1 4 ( 1 b 1 13 − 1 c 1 13 ) , b , c ∈ N I(37)-I(24)=\frac{1}{4}(\frac{1}{{b}^{\frac{1}{13}}}-\frac{1}{{c}^{\frac{1}{13}}}),b,c\in N I ( 37 ) − I ( 24 ) = 4 1 ( b 13 1 1 − c 13 1 1 ) , b , c ∈ N , then 3 ( b + c ) 3(b+c) 3 ( b + c ) is equal to
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\[ I ( x ) = ∫ d x ( x − 11 ) 11 13 ( x + 15 ) 15 13 Put x − 11 x + 15 = t ⇒ 26 ( x + 5 ) 2 d x = d t I ( x ) = 1 26 ∫ d t t 11 / 13 = 1 26 ⋅ t 2 / 13 2 / 13 \begin{aligned}
& I(x)=\int \frac{d x}{(x-11)^{\frac{11}{13}}(x+15)^{\frac{15}{13}}} \\
& \text { Put } \frac{x-11}{x+15}=t \Rightarrow \frac{26}{(x+5)^2} d x=d t \\
& I(x)=\frac{1}{26} \int \frac{d t}{t^{11 / 13}}=\frac{1}{26} \cdot \frac{t^{2 / 13}}{2 / 13}
\end{aligned} I ( x ) = ∫ ( x − 11 ) 13 11 ( x + 15 ) 13 15 d x Put x + 15 x − 11 = t ⇒ ( x + 5 ) 2 26 d x = d t I ( x ) = 26 1 ∫ t 11/13 d t = 26 1 ⋅ 2/13 t 2/13 \]
\[ I ( x ) = 1 4 ( x − 11 x + 15 ) 2 / 13 + C I ( 37 ) − I ( 24 ) = 1 4 ( 26 52 ) 2 / 13 − 1 4 ( 13 39 ) 2 / 13 = 1 4 ( 1 2 2 / 13 − 1 3 2 / 13 ) = 1 4 ( 1 4 1 / 13 − 1 9 1 / 13 ) ∴ b = 4 , c = 9 3 ( b + c ) = 39 \begin{aligned}
& \mathrm{I}(\mathrm{x})=\frac{1}{4}\left(\frac{\mathrm{x}-11}{\mathrm{x}+15}\right)^{2 / 13}+\mathrm{C} \\
& \mathrm{I}(37)-\mathrm{I}(24)=\frac{1}{4}\left(\frac{26}{52}\right)^{2 / 13}-\frac{1}{4}\left(\frac{13}{39}\right)^{2 / 13} \\
& =\frac{1}{4}\left(\frac{1}{2^{2 / 13}}-\frac{1}{3^{2 / 13}}\right) \\
& =\frac{1}{4}\left(\frac{1}{4^{1 / 13}}-\frac{1}{9^{1 / 13}}\right) \\
& \therefore \mathrm{b}=4, \mathrm{c}=9 \\
& 3(\mathrm{~b}+\mathrm{c})=39
\end{aligned} I ( x ) = 4 1 ( x + 15 x − 11 ) 2/13 + C I ( 37 ) − I ( 24 ) = 4 1 ( 52 26 ) 2/13 − 4 1 ( 39 13 ) 2/13 = 4 1 ( 2 2/13 1 − 3 2/13 1 ) = 4 1 ( 4 1/13 1 − 9 1/13 1 ) ∴ b = 4 , c = 9 3 ( b + c ) = 39 \] Answer the question to unlock