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Question 51 of 106MediumMCQ
Let the eccentricity of the hyperbola H:x2a2−y2b2=1H:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1 satisfy 1+b2a2=521+\dfrac{b^2}{a^2}=\dfrac52, and let the length of its latus rectum be 626\sqrt{2}. If y=2x+cy=2x+c is a tangent to HH, then the value of c2c^2 is equal to:
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