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Question 30 of 106MediumNUMERICAL
If the equation of the hyperbola with foci (4,2)(4,2) and (8,2)(8,2) is 3x2−y2−αx+βy+γ=03{x}^{2}-{y}^{2}-\alpha x+\beta y+\gamma =0, then α+β+γ\alpha +\beta +\gamma is equal to\_\_\_\_\_\_\_\_\_\_. Answer: 141
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