If f(x)= array|c|c| 2+2x, & -1 x

Question

If $f(x)= \begin{array}{|c|c|} 2+2x, & -1\le x<0 \ 1-\frac{x}{3}, & 0\le x\le 3 \end{array};g(x)= \begin{array}{|c|c|} -x, & -3\le x\le 0 \ x, & 0<x\le 1 \end{array}$, then range of $(fog)(x)$ is

Accepted Answer

$f(g(x))= $$2+2g(x), \& -1\le g(x)$x\in \phi $$$

And by (2) $x\in [-3,0]$ and $x\in [0,1]$

Range of $f(g(x))$ is $

Solutions · 1