Let R=a,b,c,d,e and S=1,2,3,4. Total number of onto functions f:R→S
such that f(a)=1, is equal to \_\_\_\_\_\_\_\_\_\_\_\_\_\_.
Answer: 180
Solutions · 1
Official solution
Total number of onto functions
=3!2!5!×4!=25×4×24=240
When f(a)=1, number of onto functions
=4!+2!2!4!×3!=24+36=60
So, required number of onto functions
=240−60=180