Let A=1,2,3,…,7 and let P(A) denote the power set of A. If the number of functions f:A→P(A) such that a∈f(a),\foralla∈A is mn,m and n∈N and m is least, then m+n is equal to \_\_\_\_\_\_\_\_\_.
Answer: 44
Solutions · 1
Official solution
f:A→P(A)a∈f(a)
That means 'a' will connect with subset which contain element 'a'.
Total options for 1 will be 26. (Because 26 subsets contains 1)
Similarly, for every other element
Hence, total is 26×26×26×26×26×26×26=242
Ans. 2+42=44