A ray of light through (2,1) is reflected at a point P on the Y-axis and then passes through the point (5,3). If this reflected ray is the directrix of an ellipse with eccentricity 31 and the distance of the nearer focus from this directrix is 538, then the equation of the other directrix can be
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Official solution
The reflected ray (via the image of (2,1) in the Y-axis, (−2,1), collinear with (5,3)) has direction giving slope 5+23−1=72; the directrix line is 2x−7y+11=0 (through (5,3): 10−21+11=0 ).
Distance from focus to this directrix: ea⋅(along normal)=538 combined with e=31 gives a=533 and the directrix separation e2a=5318.
Let the other directrix be 2x−7y+λ=0; distance between the parallels:
\[\frac{|\lambda-11|}{\sqrt{53}}=\frac{18}{\sqrt{53}}\Rightarrow\lambda=29\text{ or }-7.\]
\[2x-7y+29=0\quad\text{or}\quad2x-7y-7=0.\]