Consider ellipses Ek:kx2+k2y2=1, k=1,2,…,20. Let Ck be the circle which touches the four chords joining the endpoints (one on the minor axis, one on the major axis) of Ek. If rk is the radius of Ck, then the value of k=1∑20rk21 is:
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Official solution
Ek:1/kx2+1/k2y2=1, with axis endpoints (k1,0) and (0,k1). The chord joining them: kx+ky=1, at distance
\[r_k=\frac1{\sqrt{k+k^2}}\ \Longrightarrow\ \frac1{r_k^2}=k+k^2\]
from the origin.
\[\sum_{k=1}^{20}\frac1{r_k^2}=\sum_{k=1}^{20}k+\sum_{k=1}^{20}k^2=210+2870=3080.\]