Let A(α,0) and B(0,β) be the points on the line 5x+7y=50. Let the point P divide the line segment AB internally in the ratio 7:3. Let 3x−25=0 be a directrix of the ellipse E:a2x2+b2y2=1 and the corresponding focus be S. If from S, the perpendicular on the x-axis passes through P, then the length of the latus rectum of E is equal to,
Solutions · 1
Official solution
A=(10,0)B=(0,750)P=(3,5)=3ea=325a=5b=4
Length of LR=a2b2=532