The equation of the chord, of the ellipse (x^2)/(25)+(y^2)/(16)=1, whose mid-point is (3,1…

Question

The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :

Accepted Answer

$$\begin{aligned}
&\text { Equation of chord with given middle point }\
&\begin{aligned}
& \mathrm{T}=\mathrm{S}_1 \
& \Rightarrow \frac{3 \mathrm{x}}{25}+\frac{\mathrm{y}}{16}-1=\frac{9}{25}+\frac{1}{16}-1 \
& 48 \mathrm{x}+25 \mathrm{y}=144+25 \
& 48 \mathrm{x}+25 \mathrm{y}=169 \text { Ans. }
\end{aligned}
\end{aligned}$$

Solutions · 1