Consider an ellipse, whose centre is at the origin and its major axis is along the x-axis. If its eccentricity is 53 and the distance between its foci is 6, then the area (in sq. units) of the quadrilateral inscribed in the ellipse, with the vertices as the vertices of the ellipse, is:
Solutions · 1
Official solution
2ae=6,e=53⇒a=5; b2=25(1−259)=16⇒b=4.
The quadrilateral with vertices at (±a,0),(0,±b) (a rhombus) has area 4⋅21ab=2ab=2(5)(4)=40.