Let f : R \[\to\] R be defined as f(x)=x3+x−5. If g(x) is a function such that \[f(g(x)) = x,\forall 'x' \in R\], then g'(63) is equal to \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_.
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Official solution
f(x)=3x2+1
f'(x) is bijective function
and \[f(g(x)) = x \Rightarrow g(x)\] is inverse of f(x)
g(f(x))=x
\[g'(f(x))\,.\,f'(x) = 1\]
\[g'(f(x)) = {1 \over {3{x^2} + 1}}\]
Put x = 4 we get
\[g'(63) = {1 \over {49}}\]