Question 16 of 67MediumMCQ
Suppose f(x)=(7x2+3x+1)3(2x+2−x)tanxtan−1(x2−x+1). Then the value of f′(0) is equal to Solutions · 1
Official solution
f′(0)=h→0limhf(h)−f(0)=h→0lim(7h2+3h+1)3h(2h+2−h)tanhtan−1(h2−h+1)−0=π Answer the question to unlock