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Question 87 of 490MediumNUMERICAL
If the solution of the differential equation (2x+3y−2)dx+(4x+6y−7)dy=0,y(0)=3(2x+3y-2)dx+(4x+6y-7)dy=0,y(0)=3, is αx+βy+3log⁡e∣2x+3y−γ∣=6\alpha x+\beta y+3{\log }_{e}|2x+3y-\gamma |=6, then α+2β+3γ\alpha +2\beta +3\gamma is equal to \_\_\_\_\_\_\_\_\_\_\_\_. Answer: 29
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