Question 65 of 490MediumNUMERICAL
Let y=y(x) be the solution of the differential equation (tanx)1/2dy=(sec3x−(tanx)3/2y)dx,0 Solutions · 1
Official solution
dxdy+ytanx=tanxsec3x
IF=e∫tanxdx=secx
ysecx=∫tanxsec4xdx
ysecx=∫tanx(1+tan2x)sec2xdx
tanx=t
ysecx=2tanx+52(tanx)5/2+c
y(4π)=562
562×2=2+52+c→512=512+c
→c=0
y(3π)=58⋅31/4→α=2×31/4
∴α4=48 Answer the question to unlock