If \[\sin \left(\frac{y}{x}\right)=\log _e|x|+\frac{\alpha}{2}\] is the solution of the differential equation \[x \cos \left(\frac{y}{x}\right) \frac{d y}{d x}=y \cos \left(\frac{y}{x}\right)+x\] and \[y(1)=\frac{\pi}{3}\], then \[\alpha^2\] is equal to
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Official solution
Differential equation :-
\[xcosxydxdy=ycosxy+xcosxy[xdxdy−y]=x\]
Divide both sides by \[\mathrm{x}^2\]
\[\cos \frac{y}{x}\left(\frac{x \frac{d y}{d x}-y}{x^2}\right)=\frac{1}{x}\]
Let \[\frac{y}{x}=t\]
\[cost(dxdt)=x1costdt=x1dx\]
Integrating both sides
\[sint=ln∣x∣+csinxy=ln∣x∣+c\]
Using \[\mathrm{y}(1)=\frac{\pi}{3}\], we get \[\mathrm{c}=\frac{\sqrt{3}}{2}\]
So, \[\alpha=\sqrt{3} \Rightarrow \alpha^2=3\]