Let y=y1(x) and y=y2(x) be two distinct solutions of the differential equation \[\frac{d y}{d x}=x+y\], with y1(0)=0 and y2(0)=1 respectively. Then, the number of points of intersection of y=y1(x) and y=y2(x) is
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Official solution
\[{{dy} \over {dx}} = x + y\]
Let x+y=t
\[1 + {{dy} \over {dx}} = {{dt} \over {dx}}\]
\[{{dt} \over {dx}} - 1 = t \Rightarrow \int {{{dt} \over {t + 1}} = \int {dx} } \]
\[\ln |t + 1| = x + C'\]
∣t+1∣=Cex∣x+y+1∣=Cex
For \[{y_1}(x),\,{y_1}(0) = 0 \Rightarrow C = 1\]
For \[{y_2}(x),\,{y_2}(0) = 1 \Rightarrow C = 2\]
y1(x) is given by ∣x+y+1∣=exy2(x) is given by ∣x+y+1∣=2ex
At point of intersection
ex=2ex
No solution
So, there is no point of intersection of y1(x) and y2(x).