Official solution
Length of latus rectum
\[= {{|3(2) + 4( - 3) - 5|} \over 5} = {{11} \over 5}\]
\[{(x - h)^2} = {{11} \over 5}(y - k)\]
differentiate w.r.t. 'x' :-
\[2(x - h) = {{11} \over 5}{{dy} \over {dx}}\]
again differentiate
\[2 = {{11} \over 5}{{{d^2}y} \over {d{x^2}}}\]
\[{{11{d^2}y} \over {d{x^2}}} = 10\]