Question 328 of 490MediumMCQ
Solution of ydx+(x+x2y)dy=0 is: Solutions · 1
Official solution
Bernoulli form; with t=1/x: dydt−yt=1. I.F.=1/y.
\[\frac{t}{y} = \ln y+C \implies \frac{1}{xy}=\ln y+C \implies \log y-\frac{1}{xy}=C.\] Answer the question to unlock