Question 311 of 490MediumMCQ
Let y(x) solve (2+sinx)(1+y)dxdy=cosx. If y(0)=2, then y(2π) equals: Solutions · 1
Official solution
\[\int\frac{dy}{1+y}=\int\frac{\cos x}{2+\sin x}\,dx \implies 1+y=C(2+\sin x).\]
Using (0,2): C=3/2. At x=π/2: 1+y=23⋅3=29⟹y=27. Answer the question to unlock