questionr
Early access
Exams
Joint Entrance Examination
Mathematics
Differential Equations
Question 308
Question 308 of 490
Medium
MCQ
The equation of the curve through the origin satisfying
(
1
+
x
2
)
d
y
d
x
+
2
x
y
=
4
x
2
(1+x^2)\dfrac{dy}{dx}+2xy=4x^2
(
1
+
x
2
)
d
x
d
y
+
2
x
y
=
4
x
2
is:
A
(
1
+
x
2
)
y
=
x
3
(1+x^2)y=x^3
(
1
+
x
2
)
y
=
x
3
B
3
(
1
+
x
2
)
y
=
2
x
3
3(1+x^2)y=2x^3
3
(
1
+
x
2
)
y
=
2
x
3
C
(
1
+
x
2
)
y
=
3
x
3
(1+x^2)y=3x^3
(
1
+
x
2
)
y
=
3
x
3
D
3
(
1
+
x
2
)
y
=
4
x
3
3(1+x^2)y=4x^3
3
(
1
+
x
2
)
y
=
4
x
3
Check answer
Press A-D to select · Enter to check
Solutions · 1
Post your solution
Official solution
I.F.
=
1
+
x
2
=1+x^2
=
1
+
x
2
.
y
(
1
+
x
2
)
=
4
x
3
3
+
C
y(1+x^2) = \dfrac{4x^3}{3}+C
y
(
1
+
x
2
)
=
3
4
x
3
+
C
; through origin
C
=
0
C=0
C
=
0
, giving
3
y
(
1
+
x
2
)
=
4
x
3
3y(1+x^2)=4x^3
3
y
(
1
+
x
2
)
=
4
x
3
.
Answer the question to unlock
Previous
Next