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Exams
Joint Entrance Examination
Mathematics
Differential Equations
Question 303
Question 303 of 490
Medium
MCQ
The general solution of
sin
2
x
d
y
d
x
−
tan
x
−
y
=
0
\sin2x\dfrac{dy}{dx}-\sqrt{\tan x}-y=0
sin
2
x
d
x
d
y
−
tan
x
−
y
=
0
is:
A
y
tan
x
=
x
+
c
y\sqrt{\tan x}=x+c
y
tan
x
=
x
+
c
B
y
cot
x
=
tan
x
+
c
y\sqrt{\cot x}=\tan x+c
y
cot
x
=
tan
x
+
c
C
y
tan
x
=
cot
x
+
c
y\sqrt{\tan x}=\cot x+c
y
tan
x
=
cot
x
+
c
D
y
cot
x
=
x
+
c
y\sqrt{\cot x}=x+c
y
cot
x
=
x
+
c
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Solutions · 1
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Official solution
d
y
d
x
−
y
csc
2
x
=
tan
x
csc
2
x
\dfrac{dy}{dx}-y\csc2x=\sqrt{\tan x}\csc2x
d
x
d
y
−
y
csc
2
x
=
tan
x
csc
2
x
; I.F.
=
cot
x
=\sqrt{\cot x}
=
cot
x
; solving gives
y
cot
x
=
x
+
c
y\sqrt{\cot x}=x+c
y
cot
x
=
x
+
c
.
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