Question 301 of 490MediumMCQ
If the general solution of y′=xy+ϕ(yx) is yln∣cx∣=x (c arbitrary), then ϕ(2) is: Solutions · 1
Official solution
With y=vx and differentiating the given general solution, matching forms gives ϕ(1/v)=−1/v2, so at x/y=2: ϕ(2)=−1/4. Answer the question to unlock