*(Vector algebra --- not a differential equation; included as extracted.)*
Let a,b,c be mutually perpendicular, same magnitude. If r satisfies
\[\vec a\times[(\vec r-\vec b)\times\vec a]+\vec b\times[(\vec r-\vec c)\times\vec b]+\vec c\times[(\vec r-\vec a)\times\vec c]=0,\]
then r equals:
Solutions · 1
Official solution
Expanding via the BAC-CAB rule and using orthogonality and equal magnitudes gives 3r−(a+b+c)−r=0⟹r=2a+b+c.