Question 195 of 490MediumNUMERICAL
Let y=y(x) solve sin(2x2)loge(tanx2)… (schematic) dy+4xy−42xsin(x2−4π)dx=0, 0<x<2π, through (6π,1). Then y(3π) is \_\_\_\_\_\_.
Answer: 1 Solutions · 1
Official solution
Working through the linear ODE with I.F. related to ln(tan(x2/2)) and applying the given point yields y(3π)=1. Answer the question to unlock