Let y=y(x) solve y2dx+(x2−xy+y2)dy=0, passing through (1,1), and intersects y=3x at (α,3α). Then loge(3α) equals:
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Official solution
With y=vx, the homogeneous ODE reduces and integrating with (1,1) gives a relation; substituting the intersection with y=3x (i.e. v=3) yields loge(3α)=12π.