Let f be a differentiable function such that f2(x+2)=2f(x)−3(x+2)2=10∫0x(t+2)f(t)dt, x≥0. Then f(2) is equal to \_\_\_\_\_\_.
Answer: 19
Solutions · 1
Official solution
Differentiating and simplifying gives
\[(x+2)\frac{dy}{dx}-3y=3.\]
Solving: ln(y+1)=3ln(x+2)+C⇒y+1=C(x+2)3.
Using f(0)=23 as an intermediate condition, one obtains f(2)=19.