Exams Joint Entrance Examination Mathematics Definite Integration Question 93 Question 93 of 246 Medium NUMERICAL
Let [ t ] [t] [ t ] denote the largest integer less than or equal to t t t . If ∫ 0 3 ( [ x 2 ] + [ x 2 2 ] ) d x = a + b 2 − 3 − 5 + c 6 − 7 \int _{0}^{3}([{x}^{2}]+[\frac{{x}^{2}}{2}])dx=a+b\sqrt{2}-\sqrt{3}-\sqrt{5}+c\sqrt{6}-\sqrt{7} ∫ 0 3 ([ x 2 ] + [ 2 x 2 ]) d x = a + b 2 − 3 − 5 + c 6 − 7 , where a , b , c ∈ Z a,b,c\in Z a , b , c ∈ Z , then a + b + c a+b+c a + b + c is equal to \_\_\_\_\_\_\_\_\_\_.
Answer: 23
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∫ 0 3 ( [ x 2 ] + [ x 2 2 ] ) d x = ∫ 0 1 0 d x + ∫ 2 1 1 d x + ∫ 2 3 3 d x + \int _{0}^{3}([{x}^{2}]+[\frac{{x}^{2}}{2}])dx\, =\int _{0}^{1}0dx+{\int }_{\sqrt{2}}^{1}1dx+\int _{\sqrt{2}}^{\sqrt{3}}3dx+ ∫ 0 3 ([ x 2 ] + [ 2 x 2 ]) d x = ∫ 0 1 0 d x + ∫ 2 1 1 d x + ∫ 2 3 3 d x +
∫ 3 2 4 d x + ∫ 2 5 6 d x + ∫ 5 6 7 d x + ∫ 6 7 9 d x + ∫ 7 8 10 d x + ∫ 8 3 12 d x = 31 − 6 2 − 3 − 5 − 7 − 2 6 ⇒ a = 31 , b = − 6 , c = − 2 ⇒ a + b + c = 23 \begin{gathered} \int _{\sqrt{3}}^{2}4dx+\int _{2}^{\sqrt{5}}6dx+\int _{\sqrt{5}}^{\sqrt{6}}7dx+\int _{\sqrt{6}}^{\sqrt{7}}9dx+\int _{\sqrt{7}}^{\sqrt{8}}10dx+\int _{\sqrt{8}}^{3}12dx \\ =31-6\sqrt{2}-\sqrt{3}-\sqrt{5}-\sqrt{7}-2\sqrt{6} \\ \Rightarrow a=31,b=-6,c=-2 \\ \Rightarrow a+b+c=23 \end{gathered} ∫ 3 2 4 d x + ∫ 2 5 6 d x + ∫ 5 6 7 d x + ∫ 6 7 9 d x + ∫ 7 8 10 d x + ∫ 8 3 12 d x = 31 − 6 2 − 3 − 5 − 7 − 2 6 ⇒ a = 31 , b = − 6 , c = − 2 ⇒ a + b + c = 23 Answer the question to unlock