questionr
Early access
Exams
Joint Entrance Examination
Mathematics
Definite Integration
Question 60
Question 60 of 246
Medium
MCQ
For
0
<
a
<
1
0<a<1
0
<
a
<
1
, the value of the integral
∫
0
π
d
x
1
−
2
a
cos
x
+
a
2
\int _{0}^{\pi }\frac{dx}{1-2a\cos x+{a}^{2}}
∫
0
π
1
−
2
a
c
o
s
x
+
a
2
d
x
is :
A
π
2
π
+
a
2
\frac{{\pi }^{2}}{\pi +{a}^{2}}
π
+
a
2
π
2
B
π
2
π
−
a
2
\frac{{\pi }^{2}}{\pi -{a}^{2}}
π
−
a
2
π
2
C
π
1
−
a
2
\frac{\pi }{1-{a}^{2}}
1
−
a
2
π
D
π
1
+
a
2
\frac{\pi }{1+{a}^{2}}
1
+
a
2
π
Check answer
Press A-D to select · Enter to check
Solutions · 1
Post your solution
Official solution
&
I
=
∫
0
π
d
x
1
−
2
a
cos
x
+
a
2
;
0
\& I=\int _{0}^{\pi }\frac{dx}{1-2a\cos x+{a}^{2}};0
&
I
=
∫
0
π
1
−
2
a
c
o
s
x
+
a
2
d
x
;
0
Answer the question to unlock
Previous
Next