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Question 234 of 246MediumMCQ
If I=∫0π2sin⁡32xsin⁡32x+cos⁡32x dx\mathrm{I}=\int_0^{\frac{\pi}{2}} \frac{\sin ^{\frac{3}{2}} x}{\sin ^{\frac{3}{2}} x+\cos ^{\frac{3}{2}} x} \mathrm{~d} x, then ∫02Ixsin⁡xcos⁡xsin⁡4x+cos⁡4x dx\int_0^{2I} \frac{x \sin x \cos x}{\sin ^4 x+\cos ^4 x} \mathrm{~d} x equals :
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