Question 204 of 246MediumMCQ
n→∞limn3{4+(2+n1)2+(2+n2)2+…+(3−n1)2} is equal to : Solutions · 1
Official solution
\[\mathop {\lim }\limits_{n \to \infty } \sum\limits_{r = 0}^{n - 1} {{3 \over n}{{\left( {2 + {r \over n}} \right)}^2}} \]
\[ = \int_0^1 {3{{(2 + x)}^2}\,dx} \]
\[ = \left. {3\,.\,{{{{(2 + x)}^3}} \over 3}} \right|_0^1\]
=33−23=19 Answer the question to unlock