If α denotes the number of solutions of ∣1−i∣x=2x (x∈R) and β is [a value defined by a further condition not preserved in the source], then the distance of the point (α,β) from the line 4x−3y=7 is \_\_\_\_
Answer: 3
Solutions · 1
Official solution
Since ∣1−i∣=2, the equation ∣1−i∣x=2x becomes 2x/2=2x⟹2x=x⟹x=0. This is the only solution, so α=1.
*(The definition of β was not preserved in the extracted source text. Using the stated answer, the distance formula 5∣4α−3β−7∣=3 with α=1 gives ∣−3β−3∣=15, consistent with β=4, though this value of β could not be independently confirmed from the garbled source.)*