If z=x+iy,xy 0, satisfies the equation z^2+iz=0, then |z^2| is equal to :

Question

If $z=x+iy,xy
e 0$, satisfies the equation ${z}^{2}+i\vec{z}=0$, then $|{z}^{2}|$ is equal to :

Accepted Answer

$\begin{gathered} {z}^{2}=-i\vec{z} \ |{z}^{2}|=|i\vec{z}| \ |{z}^{2}|=|z| \ |z{|}^{2}-|z|=0 \ |z|(|z|-1)=0 \ |z|=0 \ 	herefore |z|=1 \ 	herefore |z{|}^{2}=1 \end{gathered}$

Solutions · 1